Solve for $y$. $$\ln y = 3t + 8$$

I tried answering the question with $$(\ln x - 8)/3$$ but I am told it's wrong. I'm really confused with the logarithms unit, so any help would be very appreciated!

  • $\begingroup$ If you'd been solving for $t$, you would've been correct! :) (Well, except that you changed the $y$ to an $x$ for some reason.) $\endgroup$ – Blue Sep 29 '18 at 0:25

There is one single trick with logarithms: isolate a logarithm and exponentiate. In your case $\log y = 3t+8$ the logarithm is already isolated, so we exponentiate: $$ e^{\log y} = e^{3t+8} $$ but $e^{\log y} = y$, so $y = e^{3t+8}$.


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