# Solving $\ln y = 3t + 8$ for $y$

Question:

Solve for $$y$$. $$\ln y = 3t + 8$$

I tried answering the question with $$(\ln x - 8)/3$$ but I am told it's wrong. I'm really confused with the logarithms unit, so any help would be very appreciated!

• If you'd been solving for $t$, you would've been correct! :) (Well, except that you changed the $y$ to an $x$ for some reason.) – Blue Sep 29 '18 at 0:25

There is one single trick with logarithms: isolate a logarithm and exponentiate. In your case $$\log y = 3t+8$$ the logarithm is already isolated, so we exponentiate: $$e^{\log y} = e^{3t+8}$$ but $$e^{\log y} = y$$, so $$y = e^{3t+8}$$.