I have been solving an OS problem in which I came across this equation where I have to find the value of H as in % but I'm not able to solve it fully. This is not a homework, I'm stuck in between and been left maths from quite some time.
3*10^-8/0.8 = H(2*10^-8 + 10^-8) + (1-H) (10^-8 + 10^-3)
My Take so far -
3*10^-8/0.8 = H(3*10^-8) + (1-H) (10^-11)
3*10^-8/0.8 = H(3*10^-8) + 10^-11 - 10^-11*H
Now I can't able to solve any further.
What I tried more is I cancelled (3*10^-8) from both LHS and RHS and I got
1/0.8 = H + (1-H)*10-11 /// ( I took 10^-11 common from 10^-11 - 10^-11*H)
So what to do after 1/0.8 = H + (1-H)*10-11