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Let R be the region bounded by the following curves. Use the disk or washer method to find the volume of the solid generated when R is revolved about he y-axis.

y=x, y=3x, y=12

Answer: $$\int_0^16 15/16 π$y^2$

This is setting up the integral only. 0, 16 were given in the graph. I followed the formula but I'm lost. Anyone can help so I can compare to my work and see what I've missed?

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  • $\begingroup$ Nobody can check your attempt if you don't post it. Anyway, good to know that you have solved it, but I don't think there is any point in keeping your question around. $\endgroup$ – user21820 Sep 22 '18 at 11:41
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I figured it out. pi(y^2-(y/4)^2)dy and solved it from there.

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