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The solution of the equation $$3^{\log_a x}+3x^{\log_a 3}=2$$ I tried to solve by taking logarithm again and bringing the power to the same level and changing two given in the R.H.S to $$2\log_3 3$$$but could not get the result please help me

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Hint:

Let $\log_ax=y\implies a^y=x$

$$2=3^y+3(a^y)^{\log_a3}=3^y+3(a^{\log_a3})^y=3^y+3(3)^y$$

Hope this is sufficient!

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$$x^{\log_a 3}=3^{\log_a x}, where \hspace{5pt} x>0 $$ Assume $$3^{\log_a x}=t$$

$$t+3 \cdot t=2$$

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Hint: $$3^{\log_{a}{x}}+3x^{\log_{a}{x}}=4\cdot 3^{\log_{a}{x}}$$ $$x=2^{\log_{3}{a}}$$

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