Could you help me with the following system of two equations? I have browsed through the forum, but I haven't found a similar problem. $$m_1x_1''(t) + k(x_1 - x_2)+ cx_1'(t) = 0$$ $$m_1x_2''(t) + k(x_2 - x_1) = D_0 \sin(\omega \cdot t)$$
I just need a method for solving it. An idea for a substitution. I have tried $x_1(t) = r(t)\cos(at),x_2(t) = r(t)\sin(at)$, but I still can't solve it.