Finding the limit of a recursive complex sequence I am currently struggling with the following exercise:

Let $z_0 = x_0+iy_0 \ne 0$ be a complex number and let the sequence $(z_n)_n$ be recursively defined as 
$$z_{n+1} = \frac{1}{2} \left( z_n+\frac{1}{z_n} \right)$$
for $n \ge 0$. Show that if $x_{0} > 0$ then $\lim_{n \to \infty} \  z_n = 1$.

$\\$
I do not know how to work with complex recursive sequences, but I suppose that, as in the real-valued case, a solution will require proving that the limit exists and then to solve the recurrency 
$$l = \frac{1}{2} \left( l + \frac{1}{l} \right)$$
In the real valued case I would try to prove that $(z_n)_n$ is monotone and bounded, but since there is no order relation in $\mathbb{C}$ I can not use this apporoach here. Could you help me?
Edit: Thanks to Ahmad Bazzi's answer I now have an idea on how to prove that $(z_n)_n$ converges: If I can prove that both sequences $(x_n)_n$ and $(y_n)_n$ (these sequences are the real and imaginary parts of each $z_n$) converge I could deduce that $(z_n)_n$ converges.
To prove that both $(x_n)_n$ and $(y_n)_n$ converge I would show that these sequences are both bounded and monotone (via induction). But unfortunately I do not get far with this approach because the definitions of these sequences is interwined, i.e.:
\begin{align}
 x_{n+1} &= \frac{1}{2}(x_n + \frac{x_n}{x_n^2 + y_n^2})\\
 y_{n+1} &= \frac{1}{2}(y_n - \frac{y_n}{x_n^2 + y_n^2})
\end{align}
and I do not know how to go on from there. Any help would be appreciated.
 A: The way I see it is that you got two recursions going on
\begin{equation}
 z_n = x_n + iy_n
\end{equation}
So
\begin{equation}
 x_{n+1} + iy_{n+1}
 =
 \frac{1}{2}
 (x_n + iy_n + \frac{1}{x_n + iy_n})
\end{equation}
The right hand side is
\begin{equation}
 \frac{1}{2}
 (x_n + iy_n + \frac{1}{x_n + iy_n})
 =
 \frac{1}{2}
 (x_n + iy_n + \frac{x_n - iy_n}{x_n^2 + y_n^2})
\end{equation}
which is
\begin{equation}
 \frac{1}{2}
 (x_n + iy_n + \frac{1}{x_n + iy_n})
 =
 \frac{1}{2}\big(  x_n + \frac{x_n}{x_n^2 + y_n^2} \big) + i\frac{1}{2}\big(y_n - \frac{y_n}{x_n^2 + y_n^2} \big)
\end{equation}
This means that 
\begin{align}
 x_{n+1} &= \frac{1}{2}(x_n + \frac{x_n}{x_n^2 + y_n^2})\\
 y_{n+1} &= \frac{1}{2}(y_n - \frac{y_n}{x_n^2 + y_n^2})
\end{align}
Solve the system
\begin{align}
 X &= \frac{1}{2}(X + \frac{X}{X^2 + Y^2})\\
 Y &= \frac{1}{2}(Y - \frac{Y}{X^2 + Y^2})
\end{align}
where the limit $L$  is
\begin{equation}
 L = X + iY
\end{equation}
First equation tells you that $X - \frac{1}{2}X = \frac{1}{2} \frac{X}{X^2 +Y^2}$, which means that 
$$X^2 + Y^2 = 1$$Replace the above condition in the $Y$ equation, you will get $Y = \frac{1}{2}(Y-Y) = 0$, hence $X^2 = 1$ so $X = \pm 1$, i.e. $L = \pm 1$. So, the limit in your problem will depend on the initial value $z_0$.
