1
$\begingroup$

From an equilateral triangle $T$ where each side have a length of $L$. What is the area of $T$?

According to the Wikipedia page of equilateral triangles, the area is $$A=\dfrac{\sqrt{3}}{4}L^2$$

I am trying to solve this problem by using the Pythagorean theorem, as explained in this question, I can split the triangle in half to try and get the height.

Using the Pythagorean theorem, $$L^2=(\dfrac{L}{2})^2 + H^2$$

I can then isolate $H$ with :

$$H=\sqrt{L^2-(\dfrac{L}{2})^2}$$

Using the $A=\dfrac{1}{2}bh$ formula. I could then conclude with : $$A=\dfrac{L\sqrt{L^2-(\dfrac{L}{2})^2}}{2}$$

As said previously, the Wikipedia page shows something very different. What went wrong?

$\endgroup$
  • $\begingroup$ Why do you think those are different? $\endgroup$ – Matthew Leingang Sep 4 '18 at 19:14
  • $\begingroup$ Factor the $L^2$ then pass it out. $\endgroup$ – Randall Sep 4 '18 at 19:15
  • 2
    $\begingroup$ $L^2-(L/2)^2=\frac{3L^2}{4}$ $\endgroup$ – Vasya Sep 4 '18 at 19:16
  • $\begingroup$ You can get properly sized parentheses that adjust to their content by preceding them with \left and \right. Please see this tutorial and reference on how to typeset math on this site. $\endgroup$ – joriki Sep 4 '18 at 20:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.