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I’m currently learning it from scratch and I think that I pretty got the general idea: Supremum is largest limit of a set/sequence and infimum is the smallest.

I’ve encountered the following definition and found it difficult to fully understand the second statement:

$S$ is a supremum of a sequence/set $A$ if and only if: 1. $$x \le S , \forall x \in A$$ And 2. $$ \forall \epsilon > 0 , \exists X_0 \in A$$ So that $$X_0 > S- \epsilon$$

I managed to understand the definition of sequence and functions limits which involves epsilons and deltas also bust this one isn’t as clear to me as them, I’d be glad to get a better explanation. Thanks for helping :)

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    $\begingroup$ It's unclear what you're asking. Could you precisely state the definition to which you'd like to compare the above definition? $\endgroup$
    – Dzoooks
    Commented Aug 18, 2018 at 13:55
  • $\begingroup$ @Dzoooks what wasn’t clear about it? $\endgroup$
    – Ozk
    Commented Aug 18, 2018 at 14:01
  • $\begingroup$ @Dzoooks the second part “2.l of the definition isn’t completely understandable to me $\endgroup$
    – Ozk
    Commented Aug 18, 2018 at 14:02
  • $\begingroup$ Compared to what? If this is the definition, then it's the definition. Would you like an intuitive explanation for why it's a good definition? Do you know another definition to which you'd like to compare this one? $\endgroup$
    – Dzoooks
    Commented Aug 18, 2018 at 14:03
  • $\begingroup$ @Dzoooks Oh, umm no I don’t know another one and yes I’d like to understand intuitively and rigorously (if possible) why it is true. I know it’s true because it’s a definition but want to know why $\endgroup$
    – Ozk
    Commented Aug 18, 2018 at 14:07

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We should clear some things up. You talk about sequences and sets, which are different things. "The supremum" of a sequence could be interpreted in two different ways:

  • The supremum of the image of the sequence (the set of values); or
  • The upper limit of the sequence (the $\limsup$).

You mean the first, so let's talk about that.

Now, the definition of the supremum that you think is unclear is actually a rephrasing of the standard one. The usual intuition is that $\sup A$ is the least upper bound, in the sense that it is an upper bound, and no number less than it is an upper bound. Formally, given a a set $A \subseteq \mathbb{R}$, we say that $x = \sup A$ iff $a \leq x$ for all $a \in A$ ($x$ is an upper bound of $A$), and $y < x$ implies that $y$ is not an upper bound of $A$.

Specifically, if $y$ is not an upper bound for $A$, then there is some $a \in A$ such that $y < a$. This directly establishes your second point. For all $\epsilon > 0$, we have $\sup A - \epsilon < \sup A$, so there must be some $a \in A$ with $$\sup A - \epsilon < a \leq \sup A.$$ This inequality finds use throughout real analysis.

The upper limit of a sequence $\{s_k\}$ is denoted $\limsup_{n \to \infty} s_n$. The concept is more technical, but closely related.

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    $\begingroup$ When I first learned it, I started thinking of the supremum as $\text{the infimum of the set of all the upper bounds}$ and of infimum as $\text{the supremum of the set of all the lower bounds}$. $\endgroup$
    – PinkyWay
    Commented Jan 24, 2020 at 21:20

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