1
$\begingroup$

From this answer I know the choice of continuous extention $\ \Gamma(z) = \int_{0}^{\infty}t^{z-1}e^{-t}dt\ $ is not unqiue.

But is that particular extension the unique best choice in some sense? E.g. is it the only one that makes $\ z\mapsto1/\Gamma(z)\ $ entire, or does it minimize some uglyness-measuring functional?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.