Find $f_y$ of $e^{x^2 + 2y^2 + 3z^2}$
How do I do this ?
I am trying to follow the formula of -
$\frac{d}{dx} e^{ax +b} = ae^{ax+b} $
Since I am differentiating the independent variable of y,
Why isn’t the partial derivative $ (f_y)$ of $e^{x^2 + 2y^2 + 3z^2} = 2e^{x^2 + 2y^2 + 3z^2} \frac{\partial}{\partial y} (x^2 + 2y^2 + 3z^2) $ ?
In fact the workings is -
$e^{x^2 + 2y^2 + 3z^2} \frac{\partial}{\partial y} (x^2 + 2y^2 + 3z^2) $
Why isn’t the ‘2’ infront if $e$ ?