Find all real numbers a and b for which the linear system has (i) no solutions (ii) infinitely many solutions and (iii)exactly one solution.

I am stuck with this linear system:

\begin{cases} x_1 + x_3 = 0 \\ ax_1 + x_2 + 2x_3 = 0 \\ 3x_1 + 4x_2 + bx_3 = 2 \end{cases}

My augmented matrix so far looks like this: R2- aR1 R3- 3R1 and then R3-4R2

\begin{bmatrix} 1 & 0 & 1 & 0 \\ 0 & 1 & 2-a & 0 \\ 0 & 0 & b-3-8-4a & 2 \end{bmatrix}

• Welcome to Maths SX! There's an error: the last row show be $\;0\quad 0\quad b-11 \color{red}+4a\quad 2$. – Bernard Aug 11 '18 at 19:59

Hint: From the first equation we get $$x_3=-x_1$$ so we can write

$$ax_1+x_2-2x_1=0$$ and

$$3x_1+4x_2-bx_1=2$$

Now we will eliminate $$x_2=2x_1-ax_1$$ so we will get

$$3x_1+4(2x_1-ax_1)-bx_1=2$$ or

$$x_1(11-4a-b)=2$$

Can you finish?

• Comments are not for extended discussion; this conversation has been moved to chat. – Daniel Fischer Aug 13 '18 at 17:45