# What is the result of $4x^2-2y^2+4z^2$?

$$2x-y = y-2z = 4$$

What is the result of $4x^2-2y^2+4z^2$?

Factoring it and rewriting the term

$$2(2x^2-y^2+2z^2)$$

Once in a while, I've tried to factor it further. However, it is impossible to proceed anymore. Could you tell what I'm actually missing?

Regards!

• $8(x-z){}{}{}{}$ – Nosrati Aug 8 '18 at 12:16

$$2x - y = 4 \Rightarrow 2x = 4 + y$$ $$y - 2z = 4 \Rightarrow 2z = y - 4$$ $$4x^2 = 16 + 8y + y^2$$ $$4z^2 = 16 - 8y + y^2$$