# Uniform convergence of a sequence of holomorphic functions

Let $U$ be an open subset of $\mathbb{C}$ and $\{f_n\}$ be a sequence of holomorphic functions. Suppose that $f_n$ converges uniformly to a function $f$ on compact subsets of $U$ and that $f$ is not identically zero in $U$ and $f(w)=0$ for some $w \in U$.

Prove that there exists $N \in \mathbb{N}$ and a sequence $\{z_n\}$ such that $f_n(z_n) = 0$ for all $n \geq N$ and $\lim_{n \rightarrow \infty}z_n = w$.

How can I prove the existence of $z_n$ and $f_n(z_n)$ is exactly 0? Any idea?

• Feels like an $\epsilon/3$ argument to me. – Adrian Keister Aug 7 '18 at 19:17
• Hint: try with Hurwitz's theorem. – Bob Aug 7 '18 at 19:27

Hint: Let $\Gamma$ be a circle around $w$ such that $\Gamma$ and its interior are in $U$, and $f_n$ is nonzero on $\Gamma$. Then $$\dfrac{1}{2\pi i} \oint_\Gamma \dfrac{f_n'(z)\; dz}{f_n(z)}$$ is the number of zeros of $f_n$ (counted by multiplicity) inside $\Gamma$