As the other answerers have pointed out, a double means that both dice show the same number. "Doublet" or "doublets" is a synonym, see the fifth definition here, or the third definition here. Hence the doubles are (in your notation) $(1,1)$, $(2,2)$, $(3,3)$, $(4,4)$, $(5,5)$, $(6,6)$. You can readily see that these six results have sums $2$, $4$, $6$, $8$, $10$, and $12$, respectively, none of which is 7. Hence the events a sum of 7
and doubles
are mutually exclusive.
As an extension of this idea (because I feel that a good answer should give you something else to think about), suppose that you have an $n$-sided die. Let $A$ and $B$ be the events
$$ A = (\text{the die sum to 7})
\qquad\text{and}\qquad B = (\text{doubles, i.e. both dice show the same number}). $$
Are these two events mutually exclusive? What if we allow the dice to be numbered differently. For example, instead of numbering the die from 1 to $n$, what if we number them from $-n$ to $n$? Are doubles
and sums to 7
still mutually exclusive? What if we don't require the numbers to be sequential? What if we don't require the numbering to be integers, but allow any real number? Are the events doubles
and sums to 7
still mutually exclusive?