$A=$$ \begin{bmatrix} 1 & 2\\ 0 & 1 \end{bmatrix} $
Find $A^n$.
My input:
$A^2= \begin{bmatrix} 1 & 2\\ 0 & 1 \end{bmatrix} \begin{bmatrix} 1 & 2\\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 4\\ 0 & 1 \end{bmatrix} $
$A^3 = \begin{bmatrix} 1 & 6\\ 0 & 1 \end{bmatrix} $ ......
$A^n = \begin{bmatrix} 1 & 2n\\ 0 & 1 \end{bmatrix} $
This was very basic approach. I want to know if there is any other way a smart trick or something to solve this problem ?