Is my solution for this question about probability correct? Also, is my interpretation of part c accurate? 

I'm not sure if my interpretation of part c is correct. Is it saying both are not pictures or spades, as in neither is picture or spade; or is it saying "not pictures" just referring to the pictures? 
 A: For (c), I believe that it means that both of the cards are not "picture" cards, and that both of them are not spades. Another way you could look at it is by picking one of the two cards randomly. The probability that it is a spade is 0. The probability that it is a "picture" card is 0.
As to your answer to (c), I did not check your math, but here is another way to solve it by simply counting the cards. First of all, we have 52 cards to choose from for our first pick, but 12 of them are face(picture) cards, so we only have 40(52 - 12) cards now. Out of the 40 cards left, 10 of them are spades(Ace ... 10), so we now have only 30(40-10) cards. So for the first card, the probability is 30/52. For the second card, the probability is 29/51, because we took the first card out of all of the cards and we also took one of the desired cards(not face or spades). In conclusion, the probability that both of the cards are not face cards or spades is 30/52 * 29/51 = 870/2652 = 0.328| Hmm, my answer disagrees with yours, so which one is correct? As a rough estimate, your answer is about 9/10, which is more than the probability of the first card(30/52); and multiplying by the probability of the second card(which is less than 1) should not make the probability go up. So I think that my answer is a bit more likely.(Of course the question was a bit confusing, so that is probably why).
P.S. Any corrections or hints welcome.
