The question is as follows:
Right triangle A has base b, height h, and area x. Right triangle B has length $2b$ and width $2h$. What is the area of rectangle B in terms of x?
I tried to substitute in values for b and h to find the area x.
$b = 4$ and $h = 2$, therefore, $x = 4$.
$2b = 8$ and $2h = 4$, therefore, area would be $16$.
This shows that the area is 4 times greater in Right Triangle B.
However, the correct answer is actually that the area is 8 times greater. I do not know why. Any help will be appreciated.