What i tried
I have solved Question 22(a) as shown on the image.
Its Question 22(b) that i need help in.
I have drawn the new parallelogram $AQRS$ which is the enlargement of $ABCD$ with the length of all its sides being $3$ times larger than that of parallelogram $ABCD$
Using the distance formula, I could find the length of $BA$ and multiplying this length by $3$ i could then find the length of $AQ$
Since length $AC$ has been found, multiplying this length by $3$ times i could then find length $AR$ and by Pythagoras theorem, length $QR$ can be found.
Letting point $R$ be $(x,y)$, we have from the distance formula
Im unsure of how to form the second equation in order to solve for $x$ and $y$. Could anyone explain. Thanks