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A producer assigns three roles to 20 actors. Roles were younger boy, old man and disable man. Find probability that 2 or more actors perform old man in the film.

P(X > 2) = ?

P(X > 2) = 1 - [P(X = 1) + P(X = 0)]

P(X > 2) = 1 - P(X = 1) - P(X = 0)

Here , we have to use the formula `P(X = x) = (nCx) p^x q^(n-x)

Here, x = 2, n = 20, q = 1 - p

What would be the value of p here ?`

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  • $\begingroup$ Is it so that every actor gets a role and that for every actor has equal chances on younger, old and disable? Without info like this (or something else) this cannot be solved. $\endgroup$ – drhab Jul 8 '18 at 11:04
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As we do not have any other information about the distribution of the roles, we can assume they are distributed uniformly. Unless we consider roles in the movies to know more about the distribution. Hence, We have: $$\mathbb{P}(X=2) = \frac{\binom{20}{2}2^{18}}{3^{20}} = \binom{20}{2} \left(\frac{2}{3}\right)^{18}\left(\frac{1}{3}\right)^{2}$$ $$\mathbb{P}(X=1) = \frac{\binom{20}{1}2^{19}}{3^{20}}=\binom{20}{1} \left(\frac{2}{3}\right)^{19}\left(\frac{1}{3}\right)^{1}$$ $$\mathbb{P}(X=0) = \frac{2^{20}}{3^{20}} = \binom{20}{0} \left(\frac{2}{3}\right)^{20}\left(\frac{1}{3}\right)^{0}$$ In the above, we choose actors for the old man role, and the others take the other two roles respectively. Now: $$\mathbb{P}(X>2) = 1 - \left(\mathbb{P}(X = 0) + \mathbb{P}(X = 1) + \mathbb{P}(X=2)\right)$$

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  • $\begingroup$ This preassumes that $p=\frac13$ but does not explain why (which is asked in the title of the question). $\endgroup$ – drhab Jul 8 '18 at 11:27
  • $\begingroup$ @drhab explained. $\endgroup$ – OmG Jul 8 '18 at 11:43
  • $\begingroup$ @OmG Thank You :) $\endgroup$ – Student28 Jul 8 '18 at 11:49

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