Induction base step: Constant functions are continuous.
Proof: Recall the (Weierstrass) definition of continuous function. For every $\epsilon$ there is a $\delta$ such that for $x_0 − \delta < x < x_0 + \delta$ implies
$f(x_0)-\epsilon < f(x) < f(x_0)+\epsilon$. This is easy. Take $\delta$ to be one (or a million).
Induction hypothesis implies inductive step: Next, you need to assume that polynomials of degree $n-1$ to be continuous, then show that a polynomial of degree $n$ is also continuous.
Here is what you need to show 1) $f(x)=x$ is continuous. This is easy. For any $\epsilon$ take $\delta$ to be equal to $\epsilon$. 2) the sum of continuous functions is continuous, and 3) the product of of two continuous functions is continuous. These last two results are in any calculus book.
With this, simply note that any polynomial of degree $n$ equal to $p_n(x)$ can be written as $p_{n-1}(x)\cdot x+constant$. (The constant is $p_n(0)$.)