# how to find the horizontal position where a projectile lands with inital height, initial velocity and angle

I am trying to find the horizontal position where a projectile lands. I have been given the initial height, initial velocity and the angle in degrees the projectile is launched at.

I have tried finding the vertical and horizontal velocity and then finding time using v = u + at and then finding the distance from v x t but this didn't give me the right answer.

This is what I have tried

• You probably mean the horizontal distance traveled, not the distance along the arc of travel, right? – MPW Jul 2 '18 at 17:12
• the horizontal velocity is going to be constant, you need to find time. Post your full solution and we'll take a look – Vasya Jul 2 '18 at 17:28

Your $t_1$ calculation is just for the upward motion to reach max height. You need to calculate the time $t_2$ it takes to go from max height to the ground which is further than the upward motion. Max height will be:
$h_{max} = h_0 + \frac{v_y}{2}\cdot t_1$
$t_2 = \sqrt{\frac{2\cdot h_{max}}{a}}$
Distance $x = v_x\cdot (t_1 + t_2)$