0
$\begingroup$

I think it's not because it seems that we can't start with zero cells to construct the cw-complex. But how to give a strict proof?

$\endgroup$
6
$\begingroup$

Hint: Here is the structure for $\mathbb R^2$: Put a $0$ cell at the vertices of the standard lattice $\mathbb Z^2$ and fill them with $2$-cells.

Of course the same argument works for $\mathbb C$, and likewise, if you can do it for $\mathbb R^{2n}$ you can do it for $\mathbb C^n$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.