# Magic Square question

• The question is flawed then. Even if we were to assume they meant $7$ instead of $3$, that would mean that the top right corner would have to be $0$, but then that diagonal would only equal $3$, not $7$. There's no solution. – Badr B Jun 10 '18 at 13:10
• Maybe, it is meant modulo $4$, but in this case, the exercise is made up badly. – Peter Jun 10 '18 at 13:14
If the upper left number was $$-2$$ instead of $$2$$, then the answer would be
$$\begin{array}{|r|r|r|} \hline \color{red}{-2} & 5 & 0 \\ \hline \color{red}{3} & \color{red}{1} & -1 \\ \hline \color{red}{2} & -3 & \color{red}{4} \\ \hline \end{array}$$