I have come across a difficult problem in my textbook.
The problem ask:
Find an equation of the plane that passes through the line of intersection of the planes $x-z=1$ and $y+2z=3$ and is perpendicular to the plane $x+y-2z=1$.
So far I found the direction vector of the line of intersection to be $<1,−2,1>$ and I have identified a point on this line when $x=0$ to be $(0,5,−1)$.
I do not know how to find the desired plane from here.
Any assistance would be appreciated.