|x+3|<-1
how to solve this algebraically. I can solve it by using graphs. 
$\begingroup$
$\endgroup$
2
-
$\begingroup$ Distinguish the cases $x+3\ge 0$ and $x+3<0$ $\endgroup$– PeterMay 12 '18 at 18:44
-
$\begingroup$ I edited the question $\endgroup$– SaraMay 12 '18 at 18:52
Add a comment
|
$\begingroup$
$\endgroup$
Your given inequality has no solution since $$\vert{x+1\vert}\geq 0$$
$\begingroup$
$\endgroup$
An absolute value is non-negative . It can't be $\;<-1$.
