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- The Monty Hall problem 11 answers
So I was reading a few maths problems and I stumbled upon the Monty Hall problem. If you are not familiar with the Monty Hall problem it goes something like this:
You are on a game show (with the objective of winning a car) and you have three doors A, B and C. Each door has one of two goats or a car behind it. You pick a door, let's say A, and before revealing what's behind A. Monty shows you what's behind C - a goat. Now do you switch your door or keep with your door?
I initially thought that it's 50-50 chance of winning if you switch, however, the answer is 2/3, and I have tried to research into this, but couldn't find an answer that explained this clearly. Please, can someone explain why the probability of winning the car is 2/3 rather than 50-50.