I was attempting to solve the following integro-differential equation using convolutions. My answer also had a convolution which did not seem right and was wondering if someone would check my process.

Problem with initial work

My final solution


$$y'(t)=1-\int_0^t y(t-\tau ) \exp (-2 \tau ) \, d\tau$$ Laplace Transform: $$s \left(\mathcal{L}_t[y(t)](s)\right)-y(0)=\frac{1}{s}-\frac{\mathcal{L}_t[y(t)](s)}{2+s}$$

We have $y(0)=1$ and solve for $\mathcal{L}_t[y(t)](s)$:

$$\mathcal{L}_t[y(t)](s)=\frac{2+s}{s (1+s)}$$ $$\mathcal{L}_t[y(t)](s)=\frac{2}{s}-\frac{1}{1+s}$$

Inverse Laplace Transform:


  • $\begingroup$ Thank you so much. I messed up on the "tails" for the initial data because I forgot it was only the first derivative. $\endgroup$ – Alex May 11 '18 at 2:04

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