Maximize the area of an isosceles triangle (let the smallest of the triangle's three angles = $2\theta$)
Triangle is bounded by a circle with radius $R$
Find angle $\theta$ which maximizes the area of the bounded triangle
Drew this out with $2\theta$ vertex pointing upward
Drew lines from center of the circle out to each vertex and noted that the angle directly below $2\theta$ (at center of circle) = $4\theta$
Next steps: possibly finding $\sin(2\theta)$ and $\cos(2\theta)?$ Not sure where to go from here. Any help welcomed.