I know that the correlation coefficient of a bivariate normal distribution is given by $$\rho_{X,Y}=\rho,$$ since $$\text{cov}(X,Y)=\rho\sigma_{X}\sigma_{Y}$$ for a bivariate normal distribution, and in general, $$\rho_{X,Y}=\frac{\text{cov}(X,Y)}{\sigma_{X}{\sigma_{Y}}}.$$ However, without basing on the parameter $\rho$ from the bivariate normal distribution, is there a way to find the correlation coefficient of a bivariate normal distribution suppose $\mu_{X}$, $\sigma_{X}$, $\mu_{Y}$, and $\sigma_{Y}$ are given? Our probability class professor said that the correlation coefficient is not always given and can change depending on other parameters (parameter $\rho$ not included). She specifically mentioned the mathematical definition of covariance, which is $$\text{cov}(X,Y)=E[(X-\mu_{X})(Y-\mu_{Y})].$$ So we have $$\text{cov}(X,Y)=\int_{-\infty}^{\infty}\int_{-\infty}^{\infty}(x-\mu_{x})(y-\mu_{y})f(x,y)\,dx\,dy$$ where $f(x,y)$ is the bivariate normal distribution function. However, if this is to be followed, then that would not eliminate the parameter $\rho$ from the distribution, and I believe will still result in $\rho\sigma_{X}\sigma_{Y}$.
So, is the correlation coefficient of a bivariate normal distribution always given (i.e. it can be changed at will depending on the behavior of the relationship of the two variables) or can it be derived using the four previously mentioned parameters?