I am learning how to write summation notation to solve Riemann Sum problems. I have a function

$f(x)=2x^3 -5x^2 +9x -5$ and I need to find the area under the curve with 8 intervals for $-4 \leq x \leq 12$ using midpoint Riemann Sum

I find the $\Delta x = 2$.

Then I use the midpoint formula $f(x_k) = a + \frac{1}{2}\Delta x + k \Delta x$ to find that $f(x_k) = -3 +2k$.

So I create the summation notation and plug the $f(x_k)$ value in place of $x$

$\sum_{k=0}^{n=7} (2(-3+2k)^3-5(-3+2k)^2+9(-3+2k)-5))2$

When I plug this into https://www.mathsisfun.com/numbers/sigma-calculator.html I get the answer 8,880 instead of the correct answer 7,648. Could some tell me where I am going wrong?


What you should have added is$$\sum_{k=0}^72\times f(-3+2k).$$Try it. You'll get $7\,648$.

  • $\begingroup$ what does $2f$ represent? $\endgroup$ – Sam May 3 '18 at 17:53
  • $\begingroup$ @Sam $2\times f$. $\endgroup$ – José Carlos Santos May 3 '18 at 17:53
  • $\begingroup$ I updated my original question because I had put $-3x+k$ instead of the correct $-3x+2k$ so it looks I am doing the same thing you suggest $\endgroup$ – Sam May 3 '18 at 18:01
  • $\begingroup$ @Sam If you are, how did you get $8\,880$? As I said, I got $7\,648$. $\endgroup$ – José Carlos Santos May 3 '18 at 18:02
  • $\begingroup$ What you should have corrected is "shoulf".-- from Review. $\endgroup$ – GNUSupporter 8964民主女神 地下教會 May 3 '18 at 18:17

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