Intersection of 4 lines in projective space I was reading about projective geometry and I came across this exercise:
Let $L_1$, $L_2$, and $M$ be three lines of $\mathbb{P}_\mathbb{R}^3$ such that $L_1 \cap M = \emptyset$, $L_2 \cap M = \emptyset$ and $L_1 \cap L_2 = \{P\}$ (a point). Show how to find all lines of $\mathbb{P}_\mathbb{R}^3$ meeting $L_1$, $L_2$, and $M$.
I am confused about how to proceed. So far the definition that I know of a line in projective space is as the span of two points: if $P = [x_0:...:x_n]$ and $Q = [y_0:...:y_n]$ then $<PQ> = \{[ \lambda x_0 + \mu y_0:...:\lambda x_n + \mu y_n] | (\lambda,\mu) \in \mathbb{R}^2\setminus\{(0,0)\} \}$. Is there any better definition that I could use, or an alternative way to visualise this problem? (I got this problem from an old past paper so it is likely that I may not have covered enough material)
Any help would be very appreciated, thank you very much!
 A: [Updated to include the second pencil of lines pointed out by user2902293.]. 
I’m going to use the language of joins and meets, which I hope you can translate into whatever formalism is used by the material that you’re studying.  
$L_1$ and $L_2$ define a unique plane $\Pi$ that can be described as their join, i.e., all non-zero linear combinations of the two lines. All lines on $\Pi$ intersect both $L_1$ and $L_2$, therefore $M$ does not lie on $\Pi$.  
There are two possibilities for a line that intersects $L_1$ and $L_2$: it is either coincident with them, passing through their intersection $P$, or its intersections with them are distinct and it is coplanar with them. In the first case, for every point $Q$ on $M$ we have a line $\mathbf{\text{Join}}[P,Q]$ that intersects $L_1$, $L_2$ and $M$. In the second case, for a line in $\Pi$ to intersect $M$, it must include the intersection of $M$ with this plane, which is a single point that does not lie on either $L_1$ or $L_2$. Therefore, all of the lines of $\mathbf{\text{Join}}[L_1,L_2]$ that pass through $\mathbf{\text{Meet}}[M,\mathbf{\text{Join}}[L_1,L_2]]$ also meet the criteria of the problem.  
For a slightly different way to describe the second set of lines, we can use the fact that $M$ defines a pencil of planes $\Pi_\alpha$ that all contain $M$. We know from above that $\mathbf{\text{Join}}[L_1,L_2]$ is not one of these planes so $\mathbf{\text{Meet}}[\Pi_\alpha,\mathbf{\text{Join}}[L_1,L_2]]$ is a line that passes through the intersection of $M$ and the plane of $L_1$ and $L_2$.
