Hi I need help with the following question, I just can't seem to figure it out and have tried multiple solutions:
The probability that a room at Old College had a refrigerator or a TV (or both) is 0.73.
A general survey of all college rooms across the university has been conducted. The survey showed that 80% of college rooms had a refrigerator or a TV (or both). Old College has 24% of the college rooms in the university. What is the probability that a randomly selected college room which had a refrigerator or a TV (or both) is an Old College room? Give your answer to three decimal places.
I tried using Bayes rule to compute 0.73*0.24/0.73*0.24+0.8*0.76 but the answer is 0.219. Can't figure out where I went wrong