What is the differential equation expression for this question? Suppose that the population of cats in a has a rate of growth proportional to the population itself. Write down a differential equation for the population $P (t)$ at time $t$ ?
 A: Well, we know that $k*P(t)=dP/dt$. This simply states that $P(t)$ is proportional to $dP/dt$.
You may be able to stop here, based on the wording of your question. It simply asks for a differential equation involving P(t) and t, which this classifies as. You can move on if you have to solve for k at some point.
First, we rearrange this to be $dP/P = kdt$. 
If we integrate both sides, 
$\int dP/P = \int kdt$
This leaves us with $ln(P) = kt + C$
Then, we do the opposite operation of the natural log (putting everything to the power of e) and we are left with:
$P = e^{kt+c}$ 
Then you solve for the initial y and the final form of the equation is:
$P=P_{0}e^{kt}$
A: Hint:  how would you express the rate of growth in terms of $P(t)$?
A: To the OP: the equation you stated in a comment to Ross is crucial (and in contradiction with your post, I should say).
So I understand that the question is to solve $P'(t)=rP(t)(1-P(t)/K)$, presumably with an initial condition $P(0)$ in $(0,K)$ (and if this is not what you ask for, please say so and I shall delete this answer).
Hint: The differential equation $P'(t)=rP(t)(1-P(t)/K)$ can be rewritten as $f(P(t))P'(t)=r$ for a function $f$ you should be able to write down. Let $g$ be any differentiable function and $G(t)=g(P(t))$. Compute $G'(t)$. Choose $g$ such that $G'(t)=P'(t)f(P(t))$. The equation $G'(t)=r$ is equivalent to $G(t)=rt+c$ for a given constant $c$. Use all this to solve the original equation.
