How many combinations are possible in the game
Noughts and crosses)?
So for example a game which looked like: (with positions 1-9)
A1 -- B1 A2 -- B2 A3 -- --
 would be one combination
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A naive estimate would be $9!=362\,880$, since there are $9$ possible first moves, $8$ for the second move, etc. This does not take into account games which finish in less than $9$ moves.
This gives a total of $255168$ possible games. This calculation doesn't take into account symmetry in the game.
I will say that the board combinations are 3^9, which is 19683 possibilities, and 2032 winning positions. The answer of 9! is related to how many ways we have to fell all the positions, rather than the possible combinations.
I have answered this question already in another post, please see the next link: https://stackoverflow.com/a/54035004/5117217