The number of prime years in a lifetime $2013$ is not a prime: $3 \times 11 \times 61$.
I was born in a prime year, and if I live as expected according to the statistics for U.S. males,
I will just reach another prime year, $2027$.  That will encompass $11$ prime years in my lifetime, which
I assume is high (because birth and probable-expiration hit primes directly).
What is the expected number of prime years in a lifetime of length $x$ years,
starting at year $n$?
I am aware that the Second Hardy-Littlewood Conjecture is likely to be false for large $n$,
but does that conjectured relationship, $\pi(x+y) \le \pi(x) + \pi(y)$, 
still yield the best interval estimate for small $n$?
 A: 
What is the expected number of prime years in a lifetime of length $x$ years, starting at
year $n$?

The exact number will be $\pi(n+x)-\pi(n)$, where $\pi(y)=\sum_{p\leq y}1 $ is the prime counting function, but how large do we expect this to be?
The primes are distributed around $n$ with density $\frac{1}{\log n}$, so the expected number would be between $\frac{x}{\log n}$ and $\frac{x}{\log (n+x)}$.  Provided that $n$ is much larger than $x$, this gives $\frac{x}{\log n}$ as the expected number of prime years.  Supposing that a man born in $2000$ lives to the ripe old age of $100$, this estimate gives approximately $13$ primes in their lifetime.  In reality there are $14$ primes between $2000$ and $2100$, which is not far off.
Note however, that if we take $n$ to be very large, it is possible that a person may live to $100$ and never experience a prime year.  Indeed, suppose that an individual was born in the year $K=101!+1$. Then even if they live a long life, and die at $100$ years old, they will  never have experienced a prime year, since each of $101!+2$, $101!+3$, $101!+4$,...,$101!+101$ are composite.
In the opposite direction, the Brun-Titchmarsh theorem tells us that $$\pi(x+n)-\pi(n)\leq \frac{2x}{\log x},$$ which gives us an upper bound on the number of prime years one can experience.  Even if one were to live to be $200$ years old, they would not see more than $75$ primes, regardless of when they were born.

Added:  The density of the primes, which is $\frac{1}{\log n}$ around $n$, goes to zero as $n\rightarrow\infty$, so unless life expectancy increases over time, the expected number of primes experienced in the average lifetime will converge to zero.  A person born around the year $1$ million A.D. would expect to see only 7 primes if she were to live to $100$.  To achieve the same expected number of primes as a woman born near the year $2000$, she would have to live to $190$.
This can also be used to give a good idea of how slowly $\log x$ grows.  For an individual's expected number of primes to be less than $1$ in their lifetime, they would have to be born past the year $10^{44}$ A.D., and considering that best estimates put the death of the sun at around $4\times 10^9$ A.D., this is very far away.
In fact, for the next $368000$ years, every individual who lives to be $100$ will experience at least one prime year.  However, there is no prime over a $114$ year period from $370261$ A.D. to $370365$ A.D., so for the unfortunate individual born in $370261$ A.D., they will experience no prime years unless they live past 114 years old.

