How i get the $x$ of the equation I have this:
$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}$ = 1
My main problem is that I want to multiply by something on both sides.
I will move $(5-\frac{5}{x})$ to side of 1, then:
$\frac{32}{20-16} = 1(5-\frac{5}{x}$)
$8 = 5 -\frac{5}{x}$ , now multiply by $x$
$8x = 5x - 5 $
$3x = 5$
$x = 5/3$
But according to symbolab it's $x = 15/19$, could you help me what I'm wrong about? I have done a lot of exercises, but I have a hard time clearing the $ x $ when it is very low.
 A: Unfortunately you can't move the $5-{5\over x}$ out of the left side because it is part of a "family" which is the denominator of the bigger fraction.
$$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=1$$
If we were to put parenthesis around the terms, it would be clearer why we can't do what you did:
$$\frac{32}{\Big(20 - \frac{16}{\big(5-\frac{5}{x}\big)}\Big)}=1$$
As you can see, the expression $5-{5\over x}$ is "stuck" inside the bigger parenthesis on the bottom, and cannot be taken out.
Having that said, let's solve the equation correctly:
Multiply both sides by the bigger parenthesis denominator:
$$32=20 - \frac{16}{5-\frac{5}{x}}$$
Subtract both sides by 20:
$$12=- \frac{16}{5-\frac{5}{x}}$$
$$-12=\frac{16}{5-\frac{5}{x}}$$
Multiply by the "middle" denominator:
$$-12\bigg({5-\frac{5}{x}}\bigg)=16$$
$$-60+\frac{60}{x}=16$$
Add 60 to both sides:
$$\frac{60}{x}=76$$
Multiply by x:
$$76x=60$$
Divide by 76:
$$x=\frac{60}{76}$$
$$x=\frac{15}{19}$$
DONE! :D
A: This step is uncorrect
$$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=1\implies \color{red}{\frac{32}{20-16} = 1(5-\frac{5}{x})}$$
following this way it should be indeed (for $x\neq 1$)
$$\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=1\implies \frac{1}{(5-\frac{5}{x})}\cdot\frac{32}{20 - \frac{16}{5-\frac{5}{x}}}=\frac{1}{(5-\frac{5}{x})}\cdot 1\implies \frac{32}{20(5-\frac{5}{x})-16} = \frac{1}{(5-\frac{5}{x})}$$
and then
$$\implies 32(5-\frac{5}{x})={20(5-\frac{5}{x})-16}\\\implies160x-160=100x-100 -16x\implies76x=60\implies x=\frac{15}{19}$$
A: What you've done when you multiply both sides by $(5-\frac{5}{x})$ is wrong. If you multiply what you've got on the left hand side by that then you do not get what you say that you get.
I suggest instead multiplying both sides by the denominator: 
$20 - \frac{16}{5-\frac{5}{x}}$.
A: Your first step is incorrect.
You cannot "move" $5-\dfrac 5x$ to one side, you are taking it out incorrectly of your fraction.
I would prefer you multiply a term on the numerator and denominator of your fraction to cancel terms out (this way the fraction also remains the same). For instance, to simplify:
$$\dfrac {16}{5-\frac 5x}=\dfrac {16}{5-\frac 5x}\cdot \dfrac xx=\dfrac{16x}{5x-5}$$
