# the sum of the series $\sum \frac{n}{2^{n}}$ [duplicate]

the sum of the series $\sum_{n=1}^\infty \frac{1}{2^{n}}$ is 1. It is easy to find since it is a g.p. the series $\sum_{n=1}^\infty \frac{n}{2^{n}}$ is convergent by ratio test. How will find the infinite sum? I am trying to rearrange the terms and to use the rearrangement theorem, but I can't complete
HINT: Use that $\sum_{n=0} nx^{n-1}=(\sum_{n=0} x^n)'=(\frac{1}{1-x})'$ for $x=\frac{1}{2}$.