In a lottery game, there is a card with $48$ numbers and you can choose $6$ numbers, or pay more and choose $7$ numbers. You win if you match all $6$ numbers drawn.
In which situation you have the most chance of winning the game?
$1$) buy a card of $7$ numbers
$2$) buy $7$ cards of $6$ numbers
Why? I can't understand this combination, but in the end I know the chance is the same.