We consider the differential equation
$ \epsilon y’’+ 2yy’ -4xy =0 $
With boundary condition $ y(0)=-1 $, $ y(1)=2$
How could we find the inner solution at $x$ nears $0$? Because if $y(0)$ changes a little, I could show that it is a boundary layer or interior layer; However at this exact $y(0)=-1$ I can't match with the outer solution successfully.