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I was asked to determine the coefficient of $x^6$ for $(1-x)^{15}$.

I used the binomial theorem as follows:

$$^{15}C_0 (1)^{15}(-x)^0 + \, ^{15}C_1 (1)^{14} (-x)^1 + \cdots + \, ^{15}C_6 (1)^9(-x)^6$$

then I evaluated $^{15}C_6$ and got $5005$. So would the coefficient simply be $5005$? Also, lets say the exponent for the $-x$ term was odd would I have made the overall coefficient $-5005$?

Sorry just trying to understand the basics of expanding the binomial theorem. Any help would be greatly appreciated.

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    $\begingroup$ You're essentially correct. I haven't read the mathematics since you didn't format it with mathjax. Please do. math.meta.stackexchange.com/questions/5020/… . Also please accept answers to your frequent questions when they help you. That's how to say "thank you" on this site. $\endgroup$ Commented Feb 20, 2018 at 16:58
  • $\begingroup$ a little mistake, it is $$5005$$ $\endgroup$ Commented Feb 20, 2018 at 16:58

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Yes, the answer is $5005$ and if the exponent were odd the coefficient would be negative for exactly the reason you say.

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