I have in total $n$ people of which $b$ are bad people and I want to randomly select $v = 5$ people. I want to calculate the probability to choose at least $3$ bad people.

I calculated it as follows:

$$P = \frac{{b\choose 3}*{n-b\choose 2}+{b\choose 4}*{n-b\choose 1}+{b\choose v}}{{n \choose v}} $$


${b\choose 3}*{n-b\choose 2} $ are the ways to choose $3$ bad people and then $2$ good ones,

${b\choose 4}*{n-b\choose 1} $ are the ways to choose $4$ bad people and then a good one,

and finally ${b\choose v}$ are the ways to choose only bad people.

Is this correct?

  • $\begingroup$ That's all good! $\endgroup$ Feb 19, 2018 at 16:42
  • $\begingroup$ In a couple of places you could replace $v$ with its known value, $5$. $\endgroup$
    – paw88789
    Feb 19, 2018 at 16:44

1 Answer 1


Your answer is good, I could understand it, but it is suggested either you write $v$ as $5$ and not have $v$ in your equation, or you have $v$ in your equation, and no $2, 3$, etc. That is for $v \le b$:

$$P = \frac{\Sigma_{x=3}^v\bigg({b\choose x}\cdot{n-b\choose v-x}\bigg)}{{n \choose v}} $$


You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .