Let $X$ be a connected topological space. Then it can be locally connected. At the other hand, a locally connected topological space can be connected. There is no implication in eather of the cases.

Is there a result (theorem), which makes, under some conditions, the one or the other presumable implication work, and under stronger conditions maybe the equivalence of both ?

Many thanks.

  • 3
    $\begingroup$ Thanks. But $(0,1)\cup(1,2)$ is open in $\mathbb{R}$ and locally connected but not connected. $\endgroup$ – user249018 Feb 10 '18 at 15:30
  • 3
    $\begingroup$ @CheerfulParsnip I think you are mixing up path-connectedness with local connectedness. $\endgroup$ – Aloizio Macedo Feb 10 '18 at 17:06
  • $\begingroup$ Nothing very interesting along these lines, but you can say for instance that for subsets of ${\mathbb R}$, connected implies locally connected. $\endgroup$ – Moishe Kohan Feb 10 '18 at 17:39
  • $\begingroup$ Oops. Deleted my comment. $\endgroup$ – Cheerful Parsnip Feb 10 '18 at 18:37
  • $\begingroup$ @MoisheCohen. But not for subsets of $\Bbb R^2$. $\endgroup$ – DanielWainfleet Feb 10 '18 at 23:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.