Let $\mathbb{Z}^2$ act on $\mathbb{R}^2$ as follows: $(1,0)$ acts by translating the plane by $(1,0)$, and $(0,1)$ acts by translating plane by $(1/2, \sqrt{3}/2)$.

Now consider the torus $\mathbb{R}^2 / \mathbb{Z}^2$. What are the finite subgroups of the group of isometries? It seems like such a classification should be possible, from the classification of wallpaper groups.

I see that the following groups are possible:

(1) Any group $G \times H$ where $G$ and $H$ are cyclic or dihedral, (2) or any subgroup of $D_{12}$, the dihedral group of order $12$.

Are there any other finite groups of isometries of this torus?

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    $\begingroup$ If $f$ is an isometry of this torus and $F$ is a lift to the universal cover, then $F$ is an isometry of Euclidean space (because local isometries are isometries in a simply connected space of nonpositive curvature). If $f$ has order $k$ and $p$ is the universal covering map, then $f^k p = pF^k$ and so $p = pF^k$, which means $F^k$ is an element of the deck group, which is the lattice you started with. Maybe this helps? $\endgroup$ – Robert Bell Feb 15 '18 at 19:46

One way to classify the ways that a finite group can act on the regular hexagonal torus $H$ is to first lift the action to the plane, then name the so-called wallpaper group $W$, and then determine whether (and in what ways) the fundamental group of $H$ can arise as a subgroup of $W$. Using Dror Bar-Natan's illustrated list of the 17 wallpaper groups, the 3 that possess a 90 degree rotation are impossible in this context. I think that the others are all possible, but there are subtle difference in group structure because of the distinction between a reflection and a glide reflection. I.e., $W$ always has a translational subgroup $T$, which is a normal subgroup, and a rotational quotient group $R$, but it can be a non-split extension of $R$ by $T$, not just a semi-direct product.

Your list of candidates is not quite complete. In the case that the orbifold quotient (of either the torus $T$ or the whole plane) is a Klein bottle, it means that you have glide reflections but no reflections. In this case the finite group acting on $H$ can be a non-split central extension of a dihedral group by a cyclic group. Besides, even after listing the finite groups that can act on $H$, a particular group in the list can act in more than one way, with subtle differences. For instance I think that there are 5 ways that the group with 2 elements acts on $H$, because the quotient can be a Klein bottle (in two ways), an annulus (again in two ways), or a sphere with four cone points of order two (in one way).


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