A six sided unbiased die with four green faces and two red faces is rolled seven times. Which of the following combinations is the likely outcome of the experiment?
(A) Three green faces and four red faces.
(B) Four green faces and three red faces.
(C) Five green faces and two red faces.
(D) Six green faces and one red face.
As probability of occurrence of green face $= 4/6 = 2/3$, and probability of occurrence of red face $= 2/6 = 1/3$.
If the die is rolled $6$ times, then expectation of green and red faces are $4$ and $2$ respectively. But die is rolled $7$ times, so I prefer $5$ green and $2$ red faces as green faces has more probability than red faces.
Could you please explain it?
Thanks in advance.