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I'm trying to solve this on: "from our union we know that 0,01% is ill from some kind of a disease. What is the probability that from a sample of 10 people at least one is ill"

My thinking so far has been something like this (X represents ill people from the sample).

$P(X\geq 1) = 1-P(X<1)^c = 1- (\frac{0,01}{100})^c \approx 9,995*10^{-4} $

Please tell me if I am like totally wrong, right ore something in between. All the possible feedback is welcomed

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The probability that at least one person in the sample is equal to one minus the probability none are ill. If the samples are independent that that probability is $(1-0.001)^{10}$ so subtract that from $1$.

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