# Is this question wrong? How can a circle be named ABC; it should be the triangle ABC, right?

Let ABC be a triangle. Let S be the circle through B tangent to CA at A and let T be the circle through C tangent to AB at A. The circles S and T intersect at A and D. Let E be the point where the line AD meets the circle ABC. Prove that D is the midpoint of AE.

• Well, we can have no idea... might be a typo – QuIcKmAtHs Jan 29 '18 at 22:09
• Or perhaps "the circle ABC" means the circumcircle of the triangle ABC? After all, 3 points uniquely define a circle – glowstonetrees Jan 29 '18 at 22:10
• Three non-colinear points always define a unique circle. So the question is not wrong, perhaps a little loosely worded. – Moriarty Jan 29 '18 at 22:11
• Well, thank you. Will consider it's circumscribed as you suggest and try to prove accordingly. Thanks again :'D – User7 Jan 29 '18 at 22:16

Assuming a triangle $A,B,C$. it seems Circle $S$ has it's origin at the midpoint of the line $AB$ (radius $\cfrac{AB}{2}$). Similarly Circle $T$ has its origin at the midpoint of $BC$ (radius $\cfrac{BC}{2}$).
For the circles to intersect at $D$ means $AB=BC$ and $AE$ is the hypotenuse of the triangle $\Bigg(\bigg(\cfrac{AB}{2}\bigg)^{2}+\bigg(\cfrac{BC}{2}\bigg)^{2}\Bigg{)}^{1/2}$.
For $D$ to be the midpoint of $AE$. $D$ would need to be the origin of the circle $ABC$ with a radius of the hypotenuse above.