I was just trying to prove the area of the circle but couldn't reach any conclusion.so here i went----- I know enter image description here For 2 identical sticks making a regular polygon we have the regular polygon as square i.e with 4 sides. For 3 identical sticks which are able to make aregular polygon we have hexagon similarly for n identical sticks we have 2n sided polygon. Now if n tends to infinity we get a circle. Now i am stuck in connecting the length of the stick and the equal angle between them with the side of the regular polygon. I cant generalise. Please help. Please note- all the sticks intersect each other at a single point i.e the centre of the geometrical figure. We get the polygons by joining the terminal end points of the sticks.enter image description here

  • $\begingroup$ How do you get a square from two sticks? $\endgroup$ – Shaun Jan 28 '18 at 16:40
  • $\begingroup$ We get the polygons by joining the terminal end points of the sticks. $\endgroup$ – Jasmine Jan 28 '18 at 16:48
  • $\begingroup$ But then two sticks is not enough for a polygon. The minimum you need is three. $\endgroup$ – Shaun Jan 28 '18 at 16:49
  • $\begingroup$ Check the pictur $\endgroup$ – Jasmine Jan 28 '18 at 16:53

I suppose the diameter is the length of the stick, let it be $d$, then we need to prove that the area of the circle with infinite sticks is $\pi\, \frac{d^2}{4}$.

The angle of the internal triangle formed with $n$ sticks is $\frac{n-1}{n}\times \frac{\pi}{2}$


\begin{align*} \text{base} &= d \, \cos{\left(\frac{n-1}{n}\cdot \frac{\pi}{2}\right)}\\ \text{height} &= \frac{d}{2}\, \sin{\left(\frac{n-1}{n}\cdot \frac{\pi}{2}\right)}\\ \end{align*}

Hence, the total area of the polygon is

\begin{align*} A &= \frac{1}{2}\cdot d \, \cos{\left(\frac{n-1}{n}\cdot \frac{\pi}{2}\right)} \cdot \frac{d}{2}\, \sin{\left(\frac{n-1}{n}\cdot \frac{\pi}{2}\right)} \times 2\, n\\ \end{align*}

Then, take the limit

\begin{align*} A &= \lim_{n\to\infty} \frac{d^2}{4} \sin{\left(\frac{n-1}{n}\cdot \pi\right)} \times n\\ &= \frac{d^2}{4}\cdot \pi \end{align*}

  • $\begingroup$ This is yet anothe amazing way to do. Thank you but can you help me in relating the sticks with side of the polygon? $\endgroup$ – Jasmine Jan 29 '18 at 4:09
  • $\begingroup$ From the vertex to the center, length is $\frac{d}{2}$, when we drop a perpendicular line to the base, distance from that point to vertex is $\frac{d}{2}\, \cos{\left(\frac{n-1}{n}\cdot \frac{\pi}{2}\right)}$. Double that for the length of the side. Clear? $\endgroup$ – gar Jan 29 '18 at 14:59
  • $\begingroup$ Well i didn't notice that. Now i got it. Thank you! $\endgroup$ – Jasmine Jan 29 '18 at 15:39
  • $\begingroup$ You're welcome! $\endgroup$ – gar Jan 29 '18 at 15:45

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