# Approximation for the following integral needed

I have following integral $$\int_0^{\infty}e^{-ax-bx^m}dx$$ where $a>0, b>0, m>1$. I can get an approximation for the above integral when $b$ is small. However, I want to get an expression for the case when $b$ is large. Any help in this regard will be highly appreciated. Thanks in advance.

• Can't you do a u-substitution to get to the case of $b$ small. Jan 24 '18 at 8:15
• @mathworker21 I am not interested in the case when $b$ is small. I am interested in the case when $b$ is not small. Jan 24 '18 at 8:18
• You said you know what to do when $b$ is small. I'm saying, if $b$ is large, then do a u-substitution to get $b$ to be small, and then apply the approximation you know holds. Jan 24 '18 at 8:21
• @mathworker21 means $x=s^{-1}u$ where $s$ is very large value. Is this what you mean? Jan 24 '18 at 8:26
• @FrankMoses: in such a case it is pretty accurate, and a lower bound can be designed by applying a step of integration by parts, then the Cauchy-Schwarz inequality. Jan 25 '18 at 2:15

Expanding the factor $e^{-ax}$ in series and integrating term-by-term yields
$$\int_0^\infty e^{-bx^m} e^{-ax}\,dx = \frac{b^{-1/m}}{m} \sum_{k=0}^{\infty} \frac{(-a)^k \operatorname{\Gamma}\!\left(\frac{k+1}{m}\right)}{k!} b^{-k/m}.$$
This series also serves as an asymptotic series as $b \to +\infty$.