Faster way of determining the coefficient of a polynomial function? Question: Determine if the leading coefficient of the function "a", is positive or negative. 
a) $$f(x)=(x-3)^2(x+1)(x+2)^3$$
In my notes I stated the sign of the leading coefficient without work but in order to get the answer now I had to expand the polynomial function out. Any help would be appreciated.
-Jack
 A: You asked for the leading coefficient of $$f(x)=(x-3)^2(x+1)(x+2)^3$$
As you see this is a polynomial of degree $6$ therefore you want to know the coefficient of $x^6$
How many $x^6$ are there in the product?
Well there is only $1$ because you need to multiply the leading coefficients of each factor to get the leading coefficient of the product.  
In our case all the leading coefficients of factors are $1$ so the leading coefficient of the product is also $1$  
A: In general once we know the roots of a polynomial function in the form
$$f(x)=k(x-x_1)(x-x_2)...(x-x_n)$$
we can easily find all the coefficient for 
$$f(x)=a_nx^2+a_{n-1}x^{n-1}+...+a_1x+a_0$$
indeed
$$a_n=k$$
$$a_{n-1}=-(x_1+x_2+...+x_n)$$
$$a_{n-2}=x_1x_2+x_1x_3...+x_{n-1}x_n$$
$$...$$
$$a_0=(-1)^{n}\prod x_i$$
Take also a look here Relation betwen coefficients and roots of a polynomial
A: You could just replace the numbers 3, 1 and 2 with zeros and apply the laws of indices.
A: Hints:


*

*the leading coefficient of the product of two polynomials is the product of the leading coefficients of those polynomials:


$$
(ax^m + \ldots [\text{powers of x < m}] \ldots)\cdot(bx^n + \ldots [\text{powers of x < n}] \ldots) \\ = ab\,x^{m+n} + \ldots [\text{powers of x < m+n}] \ldots
$$


*

*$\,f(x)\,$ is a product of monic polynomials i.e. polynomials with the leading coefficient $1$

