19
$\begingroup$

I have recently discovered that I can create letters and any shape I want by hiding parts of curves by making them complex. To generalise if I want $x>a$ then I multiply my function by $\sqrt{\frac{|x-a|}{x-a}\,}$ and replacing $x-a$ with $b-x$ I can make $x<b$.

The challenge I put forward is this:

Create an equation or set of equations, which graph the equations themselves

Is this possible?

$\endgroup$
6
  • 8
    $\begingroup$ The empty set. :) $\endgroup$
    – user14972
    Dec 17, 2012 at 22:46
  • $\begingroup$ You could say the same for a computer program quine. An empty program will print itself out ie nothing. Clever thinking though $\endgroup$
    – Jordan
    Dec 17, 2012 at 22:48
  • $\begingroup$ You'd pretty much have to give a complete language for curves and fonts before you could answer this question. I suppose there might be a general proof that there is always a quine, no matter what the font definitions and descriptive language... $\endgroup$ Dec 17, 2012 at 22:48
  • $\begingroup$ @Jordan: My answer was an homage to that one. (that was actually the submission to the obfuscated C contest that put an end to that aspect of the competition) $\endgroup$
    – user14972
    Dec 17, 2012 at 22:49
  • 21
    $\begingroup$ You might be interested in Tupper's self-referential formula $\endgroup$ Dec 17, 2012 at 22:50

1 Answer 1

2
$\begingroup$

As Ross Millikan says in the comments, Tupper's self-referential formula is a famous example.

$\endgroup$
1
  • 2
    $\begingroup$ +1, but Tupper's "self-referential" formula (which he never named so, in the excellent paper where he used it as example) just takes a bitstring (the region) and forms a bitmap out of it. This is like a program that echoes its input: sure, when given its own code as input it does print it out, but that doesn't make it a quine. However, Jakub Trávník has written a true mathematical "quine", whose graph contains all the information necessary to recreate it: here. $\endgroup$ Jun 24, 2013 at 9:13

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .